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- Жюль Верн
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- Путешествие на Луну
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- Стр. 13/99
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Answer
.
--
If
the
shot
should
preserve
continuously
its
initial
velocity
of
12,000
yards
per
second
,
it
would
require
little
more
than
nine
hours
to
reach
its
destination
;
but
,
inasmuch
as
that
initial
velocity
will
be
continually
decreasing
,
it
will
occupy
300,000
seconds
,
that
is
83hrs
.
20m
.
in
reaching
the
point
where
the
attraction
of
the
earth
and
moon
will
be
in
equilibrio
.
From
this
point
it
will
fall
into
the
moon
in
50,000
seconds
,
or
13hrs
.
53m
.
20sec
.
It
will
be
desirable
,
therefore
,
to
discharge
it
97hrs
.
13m
.
20sec
.
before
the
arrival
of
the
moon
at
the
point
aimed
at
.
Regarding
question
four
,
"
At
what
precise
moment
will
the
moon
present
herself
in
the
most
favorable
position
,
etc.
?
"
Answer
.
--
After
what
has
been
said
above
,
it
will
be
necessary
,
first
of
all
,
to
choose
the
period
when
the
moon
will
be
in
perigee
,
and
also
the
moment
when
she
will
be
crossing
the
zenith
,
which
latter
event
will
further
diminish
the
entire
distance
by
a
length
equal
to
the
radius
of
the
earth
,
i.
e.
3,919
miles
;
the
result
of
which
will
be
that
the
final
passage
remaining
to
be
accomplished
will
be
214,976
miles
.
But
although
the
moon
passes
her
perigee
every
month
,
she
does
not
reach
the
zenith
always
at
exactly
the
same
moment
.
She
does
not
appear
under
these
two
conditions
simultaneously
,
except
at
long
intervals
of
time
.
It
will
be
necessary
,
therefore
,
to
wait
for
the
moment
when
her
passage
in
perigee
shall
coincide
with
that
in
the
zenith
.
Now
,
by
a
fortunate
circumstance
,
on
the
4th
of
December
in
the
ensuing
year
the
moon
will
present
these
two
conditions
.
At
midnight
she
will
be
in
perigee
,
that
is
,
at
her
shortest
distance
from
the
earth
,
and
at
the
same
moment
she
will
be
crossing
the
zenith
.
On
the
fifth
question
,
"
At
what
point
in
the
heavens
ought
the
cannon
to
be
aimed
?
"
Answer
.
--
The
preceding
remarks
being
admitted
,
the
cannon
ought
to
be
pointed
to
the
zenith
of
the
place
.
Its
fire
,
therefore
,
will
be
perpendicular
to
the
plane
of
the
horizon
;
and
the
projectile
will
soonest
pass
beyond
the
range
of
the
terrestrial
attraction
.
But
,
in
order
that
the
moon
should
reach
the
zenith
of
a
given
place
,
it
is
necessary
that
the
place
should
not
exceed
in
latitude
the
declination
of
the
luminary
;
in
other
words
,
it
must
be
comprised
within
the
degrees
0
°
and
28
°
of
lat
.
N.
or
S
.
In
every
other
spot
the
fire
must
necessarily
be
oblique
,
which
would
seriously
militate
against
the
success
of
the
experiment
.
As
to
the
sixth
question
,
"
What
place
will
the
moon
occupy
in
the
heavens
at
the
moment
of
the
projectile
's
departure
?
"
Answer
.
--
At
the
moment
when
the
projectile
shall
be
discharged
into
space
,
the
moon
,
which
travels
daily
forward
13
°
10
'
35
"
,
will
be
distant
from
the
zenith
point
by
four
times
that
quantity
,
i.
e.
by
52
°
41
'
20
"
,
a
space
which
corresponds
to
the
path
which
she
will
describe
during
the
entire
journey
of
the
projectile
.
But
,
inasmuch
as
it
is
equally
necessary
to
take
into
account
the
deviation
which
the
rotary
motion
of
the
earth
will
impart
to
the
shot
,
and
as
the
shot
can
not
reach
the
moon
until
after
a
deviation
equal
to
16
radii
of
the
earth
,
which
,
calculated
upon
the
moon
's
orbit
,
are
equal
to
about
eleven
degrees
,
it
becomes
necessary
to
add
these
eleven
degrees
to
those
which
express
the
retardation
of
the
moon
just
mentioned
:
that
is
to
say
,
in
round
numbers
,
about
sixty-four
degrees
.
Consequently
,
at
the
moment
of
firing
the
visual
radius
applied
to
the
moon
will
describe
,
with
the
vertical
line
of
the
place
,
an
angle
of
sixty-four
degrees
.
